8x^2+63x-984=0

Solution for 8x^2+63x-984=0 equation:

8x^2+63x-984=0

a = 8; b = 63; c = -984;
Δ = b2-4ac
Δ = 632-4·8·(-984)
Δ = 35457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-\sqrt{35457}}{2*8}=\frac{-63-\sqrt{35457}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+\sqrt{35457}}{2*8}=\frac{-63+\sqrt{35457}}{16}
$